What is the result of reflecting the vector ⟨1,0⟩\langle 1, 0 \rangle⟨1,0⟩ across the line y=3xy = \sqrt{3}xy=3x?
(−12,32)(\frac{-1}{2}, \frac{\sqrt{3}}{2})(2−1,23)
(12,32)(\frac{1}{2}, \frac{\sqrt{3}}{2})(21,23)
(−12,0)(\frac{-1}{2}, 0)(2−1,0)
(12,32)×2(\frac{1}{2}, \frac{\sqrt{3}}{2}) \times 2(21,23)×2