What is the result of 3tt2−9−1t−3\frac{3t}{t^2 - 9} - \frac{1}{t-3}t2−93t−t−31?
2t+3\frac{2}{t+3}t+32
1t+3\frac{1}{t+3}t+31
3t−1t2−9\frac{3t-1}{t^2-9}t2−93t−1
2tt2−9\frac{2t}{t^2-9}t2−92t