What is the result of dividing 6(cos2π3+isin2π3)6(\cos \frac{2\pi}{3} + i \sin \frac{2\pi}{3})6(cos32π+isin32π) by 2(cosπ6+isinπ6)2(\cos \frac{\pi}{6} + i \sin \frac{\pi}{6})2(cos6π+isin6π)?
3(cosπ2+isinπ2)3(\cos \frac{\pi}{2} + i \sin \frac{\pi}{2})3(cos2π+isin2π)
4(cosπ3+isinπ3)4(\cos \frac{\pi}{3} + i \sin \frac{\pi}{3})4(cos3π+isin3π)
3(cosπ3+isinπ3)3(\cos \frac{\pi}{3} + i \sin \frac{\pi}{3})3(cos3π+isin3π)
4(cosπ2+isinπ2)4(\cos \frac{\pi}{2} + i \sin \frac{\pi}{2})4(cos2π+isin2π)