What is the radius of convergence of the series ∑n=1∞(3n)!(n!)3xn\sum_{n=1}^{\infty} \frac{(3n)!}{(n!)^3} x^n∑n=1∞(n!)3(3n)!xn?
R=1R = 1R=1
R=127R = \frac{1}{27}R=271
R=13R = \frac{1}{3}R=31
R=0R = 0R=0