What is the polar form of z=−2iz = -2iz=−2i?
2(cosfrac3pi2+isinfrac3pi2)2(\\cos \\frac{3\\pi}{2} + i \\sin \\frac{3\\pi}{2})2(cosfrac3pi2+isinfrac3pi2)
2(cosfracpi2+isinfracpi2)2(\\cos \\frac{\\pi}{2} + i \\sin \\frac{\\pi}{2})2(cosfracpi2+isinfracpi2)
2(cospi+isinpi)2(\\cos \\pi + i \\sin \\pi)2(cospi+isinpi)
2(cosfrac−pi4+isinfrac−pi4)2(\\cos \\frac{-\\pi}{4} + i \\sin \\frac{-\\pi}{4})2(cosfrac−pi4+isinfrac−pi4)