What is the Maclaurin series for f(x)=sin2(x)f(x) = \sin^2(x)f(x)=sin2(x)?
∑n=1∞(−1)n+122n−1x2n(2n)!\sum_{n=1}^{\infty} \frac{(-1)^{n+1} 2^{2n-1} x^{2n}}{(2n)!}∑n=1∞(2n)!(−1)n+122n−1x2n
∑n=1∞(−1)n22n−1x2n(2n)!\sum_{n=1}^{\infty} \frac{(-1)^n 2^{2n-1} x^{2n}}{(2n)!}∑n=1∞(2n)!(−1)n22n−1x2n
∑n=1∞(−1)n+122nx2n(2n)!\sum_{n=1}^{\infty} \frac{(-1)^{n+1} 2^{2n} x^{2n}}{(2n)!}∑n=1∞(2n)!(−1)n+122nx2n
∑n=1∞(−1)n+1x2n(2n)!\sum_{n=1}^{\infty} \frac{(-1)^{n+1} x^{2n}}{(2n)!}∑n=1∞(2n)!(−1)n+1x2n