What is the Maclaurin series for f(x)=ln(1+x)f(x) = \ln(1+x)f(x)=ln(1+x)?
∑n=1∞xnn\sum_{n=1}^{\infty} \frac{x^n}{n}∑n=1∞nxn
∑n=1∞(−1)n+1xnn\sum_{n=1}^{\infty} \frac{(-1)^{n+1} x^n}{n}∑n=1∞n(−1)n+1xn
∑n=0∞(−1)nxnn+1\sum_{n=0}^{\infty} \frac{(-1)^n x^n}{n+1}∑n=0∞n+1(−1)nxn
∑n=1∞xn−1n\sum_{n=1}^{\infty} \frac{x^{n-1}}{n}∑n=1∞nxn−1