What is the inverse transformation of T(x,y)=(x+2y,3x+y)T(x, y) = (x + 2y, 3x + y)T(x,y)=(x+2y,3x+y)?
T−1(x,y)=(x−2y5,3x−y5)T^{-1}(x, y) = (\frac{x-2y}{5}, \frac{3x-y}{5})T−1(x,y)=(5x−2y,53x−y)
T−1(x,y)=(−x+2y5,3x−y5)T^{-1}(x, y) = (\frac{-x+2y}{5}, \frac{3x-y}{5})T−1(x,y)=(5−x+2y,53x−y)
T−1(x,y)=(−x+2y−5,3x−y5)T^{-1}(x, y) = (\frac{-x+2y}{-5}, \frac{3x-y}{5})T−1(x,y)=(−5−x+2y,53x−y)
T−1(x,y)=(x−2y−5,−3x+y−5)T^{-1}(x, y) = (\frac{x-2y}{-5}, \frac{-3x+y}{-5})T−1(x,y)=(−5x−2y,−5−3x+y)