What is the inverse transformation of T(x,y)=(3x+2,4y−1)T(x, y) = (3x + 2, 4y - 1)T(x,y)=(3x+2,4y−1)?
T−1(x,y)=(x−23,y+14)T^{-1}(x, y) = (\frac{x-2}{3}, \frac{y+1}{4})T−1(x,y)=(3x−2,4y+1)
T−1(x,y)=(x+23,y−14)T^{-1}(x, y) = (\frac{x+2}{3}, \frac{y-1}{4})T−1(x,y)=(3x+2,4y−1)
T−1(x,y)=(3x−2,4y+1)T^{-1}(x, y) = (3x-2, 4y+1)T−1(x,y)=(3x−2,4y+1)
T−1(x,y)=(x3−2,y4+1)T^{-1}(x, y) = (\frac{x}{3}-2, \frac{y}{4}+1)T−1(x,y)=(3x−2,4y+1)