What is the inverse of f(x)=x1/3f(x) = x^{1/3}f(x)=x1/3?
f−1(x)=x3f^{-1}(x) = x^3f−1(x)=x3
f−1(x)=x3f^{-1}(x) = \sqrt[3]{x}f−1(x)=3x
f−1(x)=x−1/3f^{-1}(x) = x^{-1/3}f−1(x)=x−1/3
f−1(x)=1x3f^{-1}(x) = \frac{1}{x^3}f−1(x)=x31