What is the inverse function of f(x)=log2(x)f(x) = \log_2(x)f(x)=log2(x)?
f−1(x)=2xf^{-1}(x) = 2^xf−1(x)=2x
f−1(x)=x2f^{-1}(x) = x^2f−1(x)=x2
f−1(x)=1log2(x)f^{-1}(x) = \frac{1}{\log_2(x)}f−1(x)=log2(x)1
f−1(x)=log1/2(x)f^{-1}(x) = \log_{1/2}(x)f−1(x)=log1/2(x)