What is the interval of convergence for the series f(x)=∑n=1∞(x−2)2nn⋅4nf(x) = \sum_{n=1}^{\infty} \frac{(x-2)^{2n}}{n \cdot 4^n}f(x)=∑n=1∞n⋅4n(x−2)2n?
(0,4)(0, 4)(0,4)
[0,4)[0, 4)[0,4)
[0,4][0, 4][0,4]
(0,4](0, 4](0,4]