What is the general solution of y′=−y2y' = -y^2y′=−y2?
y=1x+Cy = \frac{1}{x+C}y=x+C1
y=−1x+Cy = \frac{-1}{x+C}y=x+C−1
y=x2+Cy = x^2 + Cy=x2+C
y=Ce−x2y = Ce^{-x^2}y=Ce−x2