What is the general solution of y′=x2y' = x^2y′=x2?
y=2x+Cy = 2x + Cy=2x+C
y=x3+Cy = x^3 + Cy=x3+C
y=13x3+Cy = \frac{1}{3}x^3 + Cy=31x3+C
y=x2+Cy = x^2 + Cy=x2+C