What is the general solution of y′′+4y′+4y=0y'' + 4y' + 4y = 0y′′+4y′+4y=0?
y=(C1+C2x)e−2xy = (C_1 + C_2 x)e^{-2x}y=(C1+C2x)e−2x
y=C1e2x+C2e−2xy = C_1 e^{2x} + C_2 e^{-2x}y=C1e2x+C2e−2x
y=(C1+C2x)e2xy = (C_1 + C_2 x)e^{2x}y=(C1+C2x)e2x
y=C1e−2x+C2xe−2xy = C_1 e^{-2x} + C_2 x e^{-2x}y=C1e−2x+C2xe−2x