What is the general solution of y′+2xy=xy' + 2xy = xy′+2xy=x?
y=12+Ce−x2y = \frac{1}{2} + Ce^{-x^2}y=21+Ce−x2
y=12+Cex2y = \frac{1}{2} + Ce^{x^2}y=21+Cex2
y=x+Ce−x2y = x + Ce^{-x^2}y=x+Ce−x2
y=12x+Ce−xy = \frac{1}{2}x + Ce^{-x}y=21x+Ce−x