What is the general solution of dydx=x2\frac{dy}{dx} = x^2dxdy=x2?
y=2x+Cy = 2x + Cy=2x+C
y=x33+Cy = \frac{x^3}{3} + Cy=3x3+C
y=x3+Cy = x^3 + Cy=x3+C
y=x22+Cy = \frac{x^2}{2} + Cy=2x2+C