What is the general solution of an=4an−1−4an−2a_n = 4a_{n-1} - 4a_{n-2}an=4an−1−4an−2?
an=c12n+c22na_n = c_1 2^n + c_2 2^nan=c12n+c22n
an=c12n+c2n2na_n = c_1 2^n + c_2 n 2^nan=c12n+c2n2n
an=c14n+c22na_n = c_1 4^n + c_2 2^nan=c14n+c22n
an=c12na_n = c_1 2^nan=c12n