What is the general solution of an=2an−1+3an−2a_n = 2a_{n-1} + 3a_{n-2}an=2an−1+3an−2?
an=c1(3n)+c2(−1)na_n = c_1(3^n) + c_2(-1)^nan=c1(3n)+c2(−1)n
an=c1(3n)+c2(1n)a_n = c_1(3^n) + c_2(1^n)an=c1(3n)+c2(1n)
an=c1(−3n)+c2(1n)a_n = c_1(-3^n) + c_2(1^n)an=c1(−3n)+c2(1n)
an=c1(2n)+c2(3n)a_n = c_1(2^n) + c_2(3^n)an=c1(2n)+c2(3n)