What is the general solution for y′=y2y' = y^2y′=y2?
y=1x+Cy = \frac{1}{x+C}y=x+C1
y=−1x+Cy = -\frac{1}{x+C}y=−x+C1
y=1C−xy = \frac{1}{C-x}y=C−x1
y=−1x+Cy = -\frac{1}{x}+Cy=−x1+C