What is the general solution for y′=x+yx−yy' = \frac{x+y}{x-y}y′=x−yx+y?
ln(x2+y2)=2arctan(y/x)+C\ln(x^2+y^2) = 2\arctan(y/x) + Cln(x2+y2)=2arctan(y/x)+C
arctan(y/x)=ln(x2+y2)+C\arctan(y/x) = \ln(x^2+y^2) + Carctan(y/x)=ln(x2+y2)+C
ln(x2+y2)=arctan(y/x)+C\ln(x^2+y^2) = \arctan(y/x) + Cln(x2+y2)=arctan(y/x)+C
x2+y2=Cx^2+y^2 = Cx2+y2=C