What is the general solution for y′=cos(x−y)y' = \cos(x-y)y′=cos(x−y)?
y=x−2arctan(x+C)y = x - 2\arctan(x+C)y=x−2arctan(x+C)
y=x+2arctan(x+C)y = x + 2\arctan(x+C)y=x+2arctan(x+C)
y=sin(x−y)+Cy = \sin(x-y) + Cy=sin(x−y)+C
y=cos(x+y)+Cy = \cos(x+y) + Cy=cos(x+y)+C