What is the equivalent logarithmic form of xy=zx^y = zxy=z?
logx(z)=y\log_x(z) = ylogx(z)=y
logy(z)=x\log_y(z) = xlogy(z)=x
logz(x)=y\log_z(x) = ylogz(x)=y
logx(y)=z\log_x(y) = zlogx(y)=z