What is the equation of the tangent line to the parabola y2=8xy^2 = 8xy2=8x at the point (2,4)(2, 4)(2,4)?
x−y+2=0x - y + 2 = 0x−y+2=0
x+y−6=0x + y - 6 = 0x+y−6=0
x−y−6=0x - y - 6 = 0x−y−6=0
x−2y+6=0x - 2y + 6 = 0x−2y+6=0