What is the equation of the circle with center (3,3)(3, 3)(3,3) and radius 666?
(x−3)2−(y−3)2=36(x-3)^2 - (y-3)^2 = 36(x−3)2−(y−3)2=36
(x+3)2+(y+3)2=36(x+3)^2 + (y+3)^2 = 36(x+3)2+(y+3)2=36
(x−3)2+(y−3)2=6(x-3)^2 + (y-3)^2 = 6(x−3)2+(y−3)2=6
(x−3)2+(y−3)2=36(x-3)^2 + (y-3)^2 = 36(x−3)2+(y−3)2=36