What is the equation of the chord of the circle x2+y2=16x^2 + y^2 = 16x2+y2=16 whose midpoint is (1,1)(1, 1)(1,1)?
x+y=2x+y=2x+y=2
x+y=4x+y=4x+y=4
x−y=0x-y=0x−y=0
2x+2y=12x+2y=12x+2y=1