What is the derivative of f(x)=xexf(x) = \sqrt{x} e^xf(x)=xex?
ex2x+xex\frac{e^x}{2\sqrt{x}} + \sqrt{x} e^x2xex+xex
ex2x\frac{e^x}{2\sqrt{x}}2xex
ex2x−xex\frac{e^x}{2\sqrt{x}} - \sqrt{x} e^x2xex−xex
xex\sqrt{x} e^xxex