What is the closed-form solution for an=3an−1a_n = 3a_{n-1}an=3an−1 with a0=2a_0 = 2a0=2?
an=2+3na_n = 2 + 3nan=2+3n
an=2cdot3na_n = 2 \\cdot 3^nan=2cdot3n
an=3cdot2na_n = 3 \\cdot 2^nan=3cdot2n
an=3na_n = 3nan=3n