What is the center of the hyperbola (x+1)29−(y−2)216=1\frac{(x+1)^2}{9} - \frac{(y-2)^2}{16} = 19(x+1)2−16(y−2)2=1?
(1,−2)(1, -2)(1,−2)
(−1,2)(-1, 2)(−1,2)
(3,4)(3, 4)(3,4)
(−3,−4)(-3, -4)(−3,−4)