What is the center of the hyperbola (x−1)29−(y+2)216=1\frac{(x-1)^2}{9} - \frac{(y+2)^2}{16} = 19(x−1)2−16(y+2)2=1?
(1,−2)(1, -2)(1,−2)
(−1,2)(-1, 2)(−1,2)
(9,16)(9, 16)(9,16)
(−2,1)(-2, 1)(−2,1)