What is the center of the circle (x+6)2+(y−2)2=9(x + 6)^2 + (y - 2)^2 = 9(x+6)2+(y−2)2=9?
(6,−2)(6, -2)(6,−2)
(−6,2)(-6, 2)(−6,2)
(6,2)(6, 2)(6,2)
(−6,−2)(-6, -2)(−6,−2)