What is the behavior of the solution to y′=y2y' = y^2y′=y2 with y(0)=1y(0) = 1y(0)=1 as x→1−x \to 1^-x→1−?
The solution approaches 0.
The solution approaches ∞\infty∞ (a vertical asymptote).
The solution approaches 1.
The solution oscillates.