What is the angle θ\thetaθ between the asymptotes of the hyperbola x216−y29=1\frac{x^2}{16} - \frac{y^2}{9} = 116x2−9y2=1?
2arctan(3/4)2 \arctan(3/4)2arctan(3/4)
2arctan(4/3)2 \arctan(4/3)2arctan(4/3)
arctan(3/4)\arctan(3/4)arctan(3/4)
π−2arctan(3/4)\pi - 2 \arctan(3/4)π−2arctan(3/4)