What is the angle between the asymptotes of the hyperbola x2a2−y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1a2x2−b2y2=1?
2tan−1(b/a)2\tan^{-1}(b/a)2tan−1(b/a)
tan−1(b/a)\tan^{-1}(b/a)tan−1(b/a)
2tan−1(a/b)2\tan^{-1}(a/b)2tan−1(a/b)
π/2\pi/2π/2