Verify that the Mean Value Theorem applies to f(x)=x3f(x) = x^3f(x)=x3 on [0,2][0, 2][0,2] and find the value ccc.
c=233c = \frac{2\sqrt{3}}{3}c=323
c=1c = 1c=1
c=2c = \sqrt{2}c=2
c=43c = \frac{4}{3}c=34