Verify if y=e3xy = e^{3x}y=e3x is a solution to the differential equation y′−3y=0y' - 3y = 0y′−3y=0.
Yes, because 3e3x−3(e3x)=03e^{3x} - 3(e^{3x}) = 03e3x−3(e3x)=0.
No, because the derivative is e3xe^{3x}e3x.
Yes, but only for x=0x=0x=0.
No, because it should be y′+3y=0y' + 3y = 0y′+3y=0.