Verify if y=3e2xy = 3e^{2x}y=3e2x is a solution to y′=2yy' = 2yy′=2y.
Yes, because y′=6e2xy' = 6e^{2x}y′=6e2x and 2y=6e2x2y = 6e^{2x}2y=6e2x
No, because y′=3e2xy' = 3e^{2x}y′=3e2x
Yes, because y′=3e2xy' = 3e^{2x}y′=3e2x and 2y=3e2x2y = 3e^{2x}2y=3e2x
No, because the constants do not match