Using the Taylor series for sin(x)\sin(x)sin(x), evaluate limx→0sin(x)−x+x36x5.\lim_{x \to 0} \frac{\sin(x) - x + \frac{x^3}{6}}{x^5}.limx→0x5sin(x)−x+6x3.
000
1720\frac{1}{720}7201
1120\frac{1}{120}1201
∞\infty∞