Using the series ex=∑n=0∞xnn!e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!}ex=∑n=0∞n!xn, find the sum of ∑n=0∞1n!\sum_{n=0}^{\infty} \frac{1}{n!}∑n=0∞n!1.
eee
111
ln(e)ln(e)ln(e)
000