Using the Fundamental Theorem of Calculus Part 1, find ddx∫0x(t2+1) dt\frac{d}{dx}\int_0^x (t^2+1)\,dtdxd∫0x(t2+1)dt.
x2+1x^2 + 1x2+1
x33+x\frac{x^3}{3} + x3x3+x
2x2x2x
t2+1t^2 + 1t2+1