Using the ϵ\epsilonϵ-δ\deltaδ definition, prove limx→3(2x+1)=7\lim_{x \to 3}(2x+1)=7limx→3(2x+1)=7. What is the correct δ\deltaδ in terms of ϵ\epsilonϵ?
δ=ϵ2\delta = \frac{\epsilon}{2}δ=2ϵ
δ=ϵ\delta = \epsilonδ=ϵ
δ=2ϵ\delta = 2\epsilonδ=2ϵ
δ=ϵ3\delta = \frac{\epsilon}{3}δ=3ϵ