Use uuu-substitution for ∫2zez2dz\int 2z e^{z^2} dz∫2zez2dz with u=z2u = z^2u=z2. What is the result?
ez2+Ce^{z^2} + Cez2+C
2ez2+C2e^{z^2} + C2ez2+C
ez+Ce^{z} + Cez+C
z2ez2+Cz^2 e^{z^2} + Cz2ez2+C