Use partial fractions to find the sum of ∑n=1∞1n(n+2)\sum_{n=1}^{\infty} \frac{1}{n(n+2)}∑n=1∞n(n+2)1
12\frac{1}{2}21
23\frac{2}{3}32
34\frac{3}{4}43
The series diverges