Use multiplication rule for three independent events: If P(X)=0.2P(X)=0.2P(X)=0.2, P(Y)=0.3P(Y)=0.3P(Y)=0.3, P(Z)=0.5P(Z)=0.5P(Z)=0.5, find P(Xc∩Yc∩Zc)P(X^c \cap Y^c \cap Z^c)P(Xc∩Yc∩Zc).
0.8×0.7×0.5=0.280.8 \times 0.7 \times 0.5 = 0.280.8×0.7×0.5=0.28
0.2×0.3×0.5=0.030.2 \times 0.3 \times 0.5 = 0.030.2×0.3×0.5=0.03
0.8×0.7×0.5=0.300.8 \times 0.7 \times 0.5 = 0.300.8×0.7×0.5=0.30
1−(0.2+0.3+0.5)=0.01 - (0.2 + 0.3 + 0.5) = 0.01−(0.2+0.3+0.5)=0.0