Use L'Hôpital's Rule (set up via MVT) to find limx→0ex−1−x−x2/2x3\lim_{x \to 0} \frac{e^x - 1 - x - x^2/2}{x^3}limx→0x3ex−1−x−x2/2.
16\frac{1}{6}61
12\frac{1}{2}21
111
000