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Determinantshard
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Use Cramer's rule to solve for zzz in the system: {x+2y+z=12x−y+z=2x+y+2z=3\begin{cases} x + 2y + z = 1 \\ 2x - y + z = 2 \\ x + y + 2z = 3 \end{cases}⎩⎨⎧​x+2y+z=12x−y+z=2x+y+2z=3​