Guest Session: 1 Question Remaining. Create Account to save progress.
Login
Units & Conversionshard
0:00.0

The thermal conductivity of a material is 0.5 W/(m⋅K)0.5 \text{ W/(m}\cdot\text{K)}0.5 W/(m⋅K). What is this value in cal/(cm⋅s⋅∘C)\text{cal/(cm}\cdot\text{s}\cdot^{\circ}\text{C)}cal/(cm⋅s⋅∘C)? (1 cal=4.184 J1 \text{ cal} = 4.184 \text{ J}1 cal=4.184 J, 1 m=100 cm1 \text{ m} = 100 \text{ cm}1 m=100 cm)