The system {∣x−3∣=2y2−2y=x\begin{cases} |x - 3| = 2 \\ y^2 - 2y = x \end{cases}{∣x−3∣=2y2−2y=x has how many real solution pairs (x,y)(x, y)(x,y)?
1 solution
2 solutions
3 solutions
4 solutions