The system {x+2y+3z=42x+4y+6z=8x+2y+3z=5\begin{cases} x + 2y + 3z = 4 \\ 2x + 4y + 6z = 8 \\ x + 2y + 3z = 5 \end{cases}⎩⎨⎧x+2y+3z=42x+4y+6z=8x+2y+3z=5 has:
exactly one solution
infinitely many solutions
no solution
a parametric family with one free variable