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Equations & Systemshard
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The system {2x+4y+2z=6x+2y+z=3\begin{cases} 2x + 4y + 2z = 6 \\ x + 2y + z = 3 \end{cases}{2x+4y+2z=6x+2y+z=3​ has infinitely many solutions. How many free variables are in the solution set?